chemistry lesson

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Reversibility of chemical reactions. Chemical equilibrium. Conditions for shifting the chemical equilibrium according to the principle of Le Chatelier - CHEMICAL REACTIONS - LESSON PLANS for CHEMISTRY 11 class - lesson plans - lesson plans-author's lessons-plan-lesson summary - chemistry

Lesson objectives: to consolidate the concepts of "reversibility" and "irreversibility" of chemical reactions; to generalize and to deepen students ' knowledge about chemical equilibrium, the equilibrium constant, the principle of Le Chatelier and be able to apply it to the displacement of chemical equilibrium; to give an idea of the importance of knowledge about chemical equilibrium in the production and in the nature and development of skills in solving computational problems with the use of the term "equilibrium constant".

Basic concepts: reversible and irreversible chemical reactions, chemical equilibrium, equilibrium concentrations, equilibrium constant, reaction rate, Le Chatelier principle.

Equipment: solutions ofFeCl 3; KNCS-potassium cyanide; KCl-crystal; starch paste; test tubes, water, alcohol lamp, matches, holder.

Lesson progress

I. Front-end survey

1. Determination of the rate of chemical reaction.

2. Formula expressions of speed and units of speed:

a) homogeneous reaction;

b) heterogeneous reaction.

3. List the factors that affect the rate of chemical reaction.

4. For example, the reaction of zinc (g) with hydrochloric and acetic acids to explain the effect

a) the nature of the reacting substances on the reaction rate;

b) temperature on the rate of chemical reactions: formulae of van't Hoff;

C) the contact surfaces of reacting substances for the rate of chemical reaction; compare the rate of reaction of iron in the form of powder and iron in the form of chips with hydrochloric acid.

5. How does the rate of chemical reaction depend on the concentration? The law of active masses of the reacting substances. Make a kinetic equation of a chemical reaction.

Example.

https://compendium.su/chemistry/11klas/11klas.files/image675.jpg

6. What substances are called catalysts? Inhibitors? What is the difference between their effect on the speed of a chemical reaction? The importance of catalysts and inhibitors in production, in the life of living organisms.

7. What do you need to know about a chemical reaction to determine its rate? Select the correct answers.

a) type of reaction;

b) composition and aggregate state of the initial products and final products of the reaction;

C) the concentration of all initial products of the reaction;

d) the concentration of one reaction product after a certain period of time and the value of the time interval;

e) temperature coefficient, temperature change over a certain period of time;

e) contact surface area; presence of a catalyst.

The answers are pre-recorded on the back of the Board.



Answers to questions in the front-end survey

b) the composition and aggregate state of the initial and final reaction products.

Find out if the reaction is heterogeneous or homogeneous, because the formulas for calculating the reaction rate are different for them, for a homogeneous reaction —https://compendium.su/chemistry/11klas/11klas.files/image676.jpgfor a reaction in General form AA + BB = C.

When calculating the velocity according to the law of acting masses, do not take into account substances in the solid state, as well as immiscible liquids.

https://compendium.su/chemistry/11klas/11klas.files/image677.jpg

C) the concentration of all initial reaction products, since the reaction rate is directly proportional to the concentration of reacting substances (for homogeneous reactions).

d) the speed is determined by the formula https://compendium.su/chemistry/11klas/11klas.files/image678.jpgΔC is determined by the difference in the initial and final concentration of one of the reactants. Δt — the time period for changing the concentration.

e) the temperature coefficient y for each reaction is known, it is necessary for calculating the change in the reaction rate as a result of an increase or decrease in temperature according to the Vanth-Hoff law https://compendium.su/chemistry/11klas/11klas.files/image679.jpg

f) the contact surface of reactants is taken into account in heterogeneous reactions according to the formula https://compendium.su/chemistry/11klas/11klas.files/image680.jpg

The more fragmented a substance is, the smaller the unit area, and the faster the reaction rate. Catalyst-accelerator. A substance that ultimately increases the reaction rate, but is not consumed by itself. The action of an inhibitor is the opposite of that of a catalyst.

Catalysts are substances that change the reaction mechanism and direct it in a more favorable direction of energy-lessEa. They do not change qualitatively or quantitatively.




II. Independent work

Option I

Option II

1. Make an expression of the speed of a chemical reaction according to the law of acting masses.

https://compendium.su/chemistry/11klas/11klas.files/image681.jpg

https://compendium.su/chemistry/11klas/11klas.files/image682.jpg

2. How will the response rate change based on the task condition, decrease or increase?

https://compendium.su/chemistry/11klas/11klas.files/image683.jpg

https://compendium.su/chemistry/11klas/11klas.files/image684.jpg

3. Calculate the speed

of a homogeneous reaction

a heterogeneous reaction

by the condition:

https://compendium.su/chemistry/11klas/11klas.files/image685.jpg

https://compendium.su/chemistry/11klas/11klas.files/image686.jpg

Perform a self-check.



Answers to self-study questions

Option I

https://compendium.su/chemistry/11klas/11klas.files/image687.jpg

Answer: the reaction speed will increase by 27 times.

https://compendium.su/chemistry/11klas/11klas.files/image688.jpg



Answer: VGOM.= 0.00017 mol/l · sec.



Option II

https://compendium.su/chemistry/11klas/11klas.files/image689.jpg

Answer: the reaction speed will increase by 16 times.

https://compendium.su/chemistry/11klas/11klas.files/image690.jpg

Answer: Vhetero.= 2.22 mol/sec · mm2.



II. Learning new material

Plan of presentation:

1. Reactions are irreversible and reversible. Signs of irreversibility.

2. Chemical equilibrium. The constant of chemical equilibrium.

3. Factors that cause chemical equilibrium mixing. The Le Chatelier Principle. Experiment.

4. Solving computational problems of the topic.

Task: from the proposed equations of chemical reactions to choose the reactions:

a) irreversible;

b) reversible.

https://compendium.su/chemistry/11klas/11klas.files/image691.jpg

Irreversible reactions have signs of irreversibility:

https://compendium.su/chemistry/11klas/11klas.files/image692.jpg — there's been a fallout.

https://compendium.su/chemistry/11klas/11klas.files/image693.jpg — a weak electrolyte was formed, which decomposes into water and carbon dioxide.

https://compendium.su/chemistry/11klas/11klas.files/image694.jpg — water was formed — a very weak electrolyte.



The rest of the reactions under the same conditions can occur both in the forward and in the reverse direction. They are reversible.

https://compendium.su/chemistry/11klas/11klas.files/image695.jpg

It is known that most reactions are reversible. If we are talking about a closed system, then under certain conditions, the irreversible reaction becomes reversible.

Example:

a) in an open system, the reactionhttps://compendium.su/chemistry/11klas/11klas.files/image696.jpgis irreversible;

b) in a closed system — it becomes reversible:

https://compendium.su/chemistry/11klas/11klas.files/image697.jpg

Let's look in more detail at the processes occurring in reversible reactions for a conditional reaction.

https://compendium.su/chemistry/11klas/11klas.files/image698.jpg

According to the law of acting masses, we will determine the rates of forward and reverse reactions.

https://compendium.su/chemistry/11klas/11klas.files/image699.jpg because over time WithA and CBdecreases, then the rate of direct reaction decreases. Since the direct reaction results in the formation of products C and D, and the reaction is reversible, the speed of the reverse reaction begins to increase.

https://compendium.su/chemistry/11klas/11klas.files/image700.jpg

There comes a point when the rates of forward and reverse reaction become equal: VPR. = VOBR.and the concentrations of reactants and end products of the reaction remain unchanged. They are called equilibrium concentrations. This equilibrium in the system is called a moving or dynamic one. We should consider Fig. 34 p. 142 of the textbook, which shows graphs of changes in the concentration and rates of reactions of irreversible and reversible.

Reactions are irreversible — with increasing time, the concentrations of the initial substances decrease to 0, and the concentration of the final products increases. The reaction rate decreases to 0. the Reactions are reversible — the concentrations of the initial substances decrease, while the concentrations of the final products of the reaction increase in a certain period of time. The speed of the direct reaction decreases, and the speed of the reverse reaction increases over the same period of time. There is a moment of equalization of the rates of forward and reverse reactions, and the concentrations of the initial products and final products of the reaction remain unchanged.



image261



The state of a system at which the rate of direct reaction is equal to the rate of reverse reaction is called chemical equilibrium.

The state of chemical equilibrium can be given a quantitative characteristic by applying the law of acting masses, through the chemical equilibrium constant tothe equation of equalmass .— constant value for a given reversible reaction. It shows the ratio between the concentrations of the reaction products (numerator) and the initial substances (denominator), which is established at equilibrium.

In the case of a chemical reaction in General form

https://compendium.su/chemistry/11klas/11klas.files/image702.jpg the equilibrium concentrations of substances are [A]; [B]; [C]; [D].

https://compendium.su/chemistry/11klas/11klas.files/image703.jpg

because at the moment of chemical equilibrium

https://compendium.su/chemistry/11klas/11klas.files/image704.jpg

If Kis equal. > 1-concentrations of reaction products predominate over the concentration of starting products in a direct reaction, the system is directed towards →

If Kis equal. < 1, the concentration of the initial reaction products dominated by the concentration of end products of the reaction, the system is directed toward the reverse reaction ←

If Kis equal. = 1, the concentration of the initial reaction products and the final ones remain unchanged, since the rates of forward and reverse reactions are equal, and chemical equilibrium has arrived https://compendium.su/chemistry/11klas/11klas.files/image705.jpg

In the case of heterogeneous reactions, the expression of the equilibrium constant includes concentrations of substances that are in the gas and liquid phase.

Example: https://compendium.su/chemistry/11klas/11klas.files/image706.jpg

https://compendium.su/chemistry/11klas/11klas.files/image707.jpg



The value of the equilibrium constant depends on the nature of the reacting substances and temperature. The catalyst lowersEactivatesboth the forward and reverse reaction by the same amount and only accelerates the onset of equilibrium.

The state of chemical equilibrium can be maintained for a long time under unchanged external conditions: temperature, concentration of initial substances or final pressure products (if gases are involved in the reaction).

If you change these conditions, you can move the system from one equilibrium state to another that meets the new conditions.

Such a shift is called a displacement or shift of balance. Displacement control can be predicted using Le Chatelier's principle, 1884.

When the equilibrium system is influenced from the outside (to change the concentration, pressure, temperature), the equilibrium shifts in the direction of the reaction (direct or reverse) that weakens this effect.

1) Change in concentration:

a) if we increase from the final products, the balance shifts towards the formation of initial products, i.e. the reverse reaction prevails:

https://compendium.su/chemistry/11klas/11klas.files/image708.jpg

b) we increase the concentration of initial products, the balance shifts towards the formation of final products, a direct reaction prevails:

https://compendium.su/chemistry/11klas/11klas.files/image709.jpg

C) when the concentration of end products decreases, the equilibrium reaction shifts towards their formation, and the direct reaction prevails:

https://compendium.su/chemistry/11klas/11klas.files/image710.jpg

d) when the concentration of initial reaction products decreases, the equilibrium shifts towards the formation of initial reaction products, the reverse reaction prevails:

image262

2) Influence of pressure change:

a) when the pressure increases, the equilibrium shifts in the direction of the reaction, in which the volume of formed gaseous products decreases:

R^ a, in the direction of the least amount of;

b) when the pressure decreases, the equilibrium shifts in the direction of the reaction, in which the volume of formed gaseous products increases:

P↓ — in the direction of the maximum volume.

Example. https://compendium.su/chemistry/11klas/11klas.files/image712.jpg

a) P↑ — direct reactionhttps://compendium.su/chemistry/11klas/11klas.files/image713.jpg(direct P↑);

b) P↓ — reverse reactionhttps://compendium.su/chemistry/11klas/11klas.files/image714.jpg(reverse P↓);

C) if the volumes of gaseous products are the same in both the forward and reverse reaction — the change in pressure does not cause a shift in the equilibrium.

Example: https://compendium.su/chemistry/11klas/11klas.files/image715.jpg

3) Influence of temperature change:

a) when the temperature rises, the chemical equilibrium shifts towards the endothermic reaction.

t ° ↑ - to the side - Q;

b) when the temperature drops, the chemical equilibrium shifts towards the endothermic reaction.

t ° ↓ - to the side + Q;

Example. https://compendium.su/chemistry/11klas/11klas.files/image716.jpg

https://compendium.su/chemistry/11klas/11klas.files/image717.jpg

The principle of Le Chatelier is also applicable to the processes of evaporation, condensation, melting, and crystallization. When producing the most important chemical products, they take into account the peculiarities of chemical reactions, especially reversible ones, and find optimal conditions that ensure maximum product yield.

Further, students are shown experiments proving the possibility of shifting the chemical equilibrium by applying factors:

a) temperature change.

Add solution I2 to the starch paste. There is a blueness, because the starch macromolecule-amylose-reacts with I2, forms a colored complex — an amylose molecule in the form of a spiral, surrounded by iodine molecules. 2There are six glucose bases around each I2 molecule. When heated, this complex is destroyed and the color disappears when cooled — the complex is formed again and the color is restored.

https://compendium.su/chemistry/11klas/11klas.files/image718.jpg

b) changes in the concentration of initial and final products of the reaction.

In four test tubes add 2 ml of water and 1-2 drops of KNCS

(rhodanide) of potassium; and 1-2 dropshttps://compendium.su/chemistry/11klas/11klas.files/image719.jpgof the solution became light red in all test tubes.

https://compendium.su/chemistry/11klas/11klas.files/image720.jpg

Add 2-3 drops of FeCl 3 to test tube # 13 — the color increases, there is a direct reaction → Vdirect > > VOBR.

Add 2-3 drops of KNCS to test tube # 2 — the color increases, there is a direct reaction → Vdirect > > VOBR.

In test tube # 3 add CSl-color disappears, there is a reverse reaction ← Vdirect < VOBR.

Test tube # 4 - for comparison.



III. Generalizations and conclusions

Thus, in this lesson, we have studied in more depth the chemical equilibrium that can occur in reversible chemical reactions, and also got an idea of the factors that cause the shift of chemical equilibrium in the direction of a direct or reverse reaction, experimentally confirmed this.



IV. Homework assignment

§ 14, # 1-4, problems # 7, 8.



V. Fixing and solving calculation problems

Task. № 1(1) § 14.

https://compendium.su/chemistry/11klas/11klas.files/image721.jpg

https://compendium.su/chemistry/11klas/11klas.files/image722.jpg

https://compendium.su/chemistry/11klas/11klas.files/image723.jpg towards a lower volume.

Task. № 2 (1) § 14.

https://compendium.su/chemistry/11klas/11klas.files/image724.jpg

https://compendium.su/chemistry/11klas/11klas.files/image725.jpg towards a lower volume.

Task. 5 (1) § 14.

https://compendium.su/chemistry/11klas/11klas.files/image726.jpg https://compendium.su/chemistry/11klas/11klas.files/image727.jpg

1) γH2 — spent to obtain 0.09 HI

https://compendium.su/chemistry/11klas/11klas.files/image728.jpg

https://compendium.su/chemistry/11klas/11klas.files/image729.jpg

2) γI2 — spent to obtain 0.09 NI

https://compendium.su/chemistry/11klas/11klas.files/image730.jpg

Answer: WithI2 ex. = 0.05 (mol/l); WithH2 (ex.)= 0.07 (mol/l).