Internal energy of the ideal gas Solutions and answers for classroom

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Solutions and answers for classroom tasks and homework

Task 2.

Helium is a monatomic gas, therefore its internal

energy is determined by the formula https://static-interneturok.cdnvideo.ru/content/konspekt_image/272512/7e76b360_66a0_0133_f93f_12313c0dade2.png. At a temperature

Т = 127+273= 400 К this energy is equal U=3/2*8,31*400=5000 J

1.

What is the internal energy of 10 moles of argon at 270С ?

U=3/2* ʋRT
T=273+27=300 K
Consequently U=3/2 *10*8.31*300=37395 J

2.

Find the internal energy U mass m=20 g oxygen at temperature t = 10 °С.

Given:

 

m = 20 g = 0,02 kg

Т1 =10 °С = 283 К

U - ?    

Solution:

 

   

http://www.bog5.in.ua/problems/sav/molecular/img_mol/clip_image002_0009.pngThe internal energy of a gas.

 

3.

Find the internal energy U diatomic gas, located in a vessel V = 2 L under pressure

р = 150 kPa.

 Given:

 

i = 5

V = 2 L = 2·10-3 m3

р = 150 kPa = 150·103 Pа

U - ?

Solution:

 

Тhe internal energy  diatomic gas 

http://www.bog5.in.ua/problems/sav/molecular/img_mol/clip_image002_0008.png

 

           http://www.bog5.in.ua/problems/sav/molecular/img_mol/clip_image004_0005.png

http://www.bog5.in.ua/problems/sav/molecular/img_mol/clip_image006_0005.png

The internal energy http://www.bog5.in.ua/problems/sav/molecular/img_mol/clip_image008_0002.png750 J 

 

Homework solutions and answers

1)      Nitrogen is diatomic gas (N2).

 

U = ·nRT

 

n =         (M(N2) = 28·10-3 kg/mole)

 

U = ··8.314 J/(mole·K)·283 K

 

U ≈ 4.2 kJ

 

2)      Helium is monatomic gas (He).

 

U = ·nRT

 

PV = nRT

 

U = ·PV

 

U = ·100·103 Pa·60 m3

 

U = 9 MJ

 

3)      n = const   (m = const)

 

 =

 

ΔT = T2 – T1

 

ΔU = ·nRΔT

 

P2 = 3P1

 

V2 =

 

 =  => T2 = 1.5T1

 

 

ΔU = ·nR0.5·T1

 

U1 = ·nRT1

 

U2 = ·nR·1.5T1

 

Internal energy will be increased by half of initial

 

OR

 

Internal energy will be increased by 1.5 times

 

 

 


 

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