Mark scheme (jigsaw)
Mark Scheme
Group 1
Part I
1 C 2D 3C
Part
II
1
2 (a)
(b)
Group 2
Part I
1A 2B 3C
Part II
1
2
Group 3
Part 1
1 D 2 D 3C
Part II
1
2
Mark Scheme (simulation)
1 The magnitude of the force between applied and restoring force is the same but opposite in direction.
2 unit of k = Nm-1
3 As the value of k increases, elongation decreases (∆x) /
(inversely proportional)
4 As the applied force increases, the elongation increases (∆x) / directly proportional
5 Table 1: k = 200 Nm-1
Trial |
Applied Force / N |
Elongation / m |
1 |
20 |
0.100 |
2 |
40 |
0.200 |
3 |
60 |
0.300 |
4 |
80 |
0.400 |
5 |
100 |
0.500 |
Table 2: k = 400 Nm-1
Trial |
Applied Force / N |
Elongation / m |
1 |
20 |
0.050 |
2 |
40 |
0.100 |
3 |
60 |
0.150 |
4 |
80 |
0.200 |
5 |
100 |
0.250 |
f. Graph
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6 (a) The gradient of graph 2 is much steeper than the gradient of graph 1/ gradient of graph 2 is greater than the gradient of graph 1 [1]
The gradient of graph 1 is the same as the spring constant, k. (same as the gradient of graph 2) [1]
(b) The gradient of F-∆x graph is the spring constant, k. [1]
7/8 Varied answers
9 Parallel: when the springs are connected in parallel, the total spring constant increases. Therefore elongation will be smaller thab that each spring on its own. [1]
Series: when the springs are connected in series, the total spring constant decreases. Therefore elongation will be greater than that of each spring on its own.
10
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