Mechanical properties of the solid bodies Mark schemes

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  • 04.05.2020
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Mark scheme (jigsaw)

Mark Scheme

Group 1

Part I

1 C      2D       3C

 

Part II

1

 

 

 

 

 

 

 

 

 

 

2 (a)

 

 

 

  (b)

 

 

 

Group 2

Part I

1A       2B       3C

 

Part II

1

 

 

 

 

 

 

 

 

2

 

 

 

 

 

Group 3

Part 1

1 D      2 D      3C

Part II

1

 

 

 

 

 

 

 

 

 

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Mark Scheme (simulation)

 

1          The magnitude of the force between applied and restoring force is the same but opposite in direction.

2          unit of k = Nm-1

3          As the value of k increases, elongation decreases (∆x) /

(inversely proportional)

4          As the applied force increases, the elongation increases (∆x) / directly proportional

5          Table 1: k = 200 Nm-1

Trial

Applied Force / N

Elongation / m

1

20

0.100

2

40

0.200

3

60

0.300

4

80

0.400

5

100

0.500

 

Table 2: k = 400 Nm-1

Trial

Applied Force / N

Elongation / m

1

20

0.050

2

40

0.100

3

60

0.150

4

80

0.200

5

100

0.250

f. Graph

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


6          (a) The gradient of graph 2 is much steeper than the gradient of graph 1/ gradient of graph 2 is greater than the gradient of graph 1  [1]

            The gradient of graph 1 is the same as the spring constant, k. (same as the gradient of graph 2)                                      [1]

            (b) The gradient of F-∆x graph is the spring constant, k. [1]

7/8       Varied answers

9          Parallel: when the springs are connected in parallel, the total spring constant increases. Therefore elongation will be smaller thab that each spring on its own. [1]

            Series:  when the springs are connected in series, the total spring constant decreases. Therefore elongation will be greater than that of each spring on its own.

 

10  


 

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