Приложения2ФО_1 Лист оценивания ответы

1    a    θ =  ´ 2π =  » 0.52 рад                                                                                                [1]

b    θ =  ´ 2π » 3.7 рад                                                                                                         [1]

c    θ =  ´ 2π » 8.7 ´ 10⁻⁴ рад                                                                                              [1]

2    a    θ =  ´ 360 = 57.3° » 57°                                                                                                   [1]

b    θ =  ´ 360 » 230°                                                                                                            [1]

c    θ =  ´ 360 » 8.6°                                                                                                           [1]

3    a    88 дней равно  2π радиане
θ =  ´ 2π = π rad                                                                                                              [1]

b    θ =  ´ 2π » 0.071 rad (4.1°)                                                                                              [1]

4    a    w =  =                                                                                                                   [1]
w = 7.5 ´ 10⁵ рад  с⁻¹                                                                                                             [1]

b    a =                                                                                                                                  [1]
a =                                                                                                                            [1]
a = 1.125 м с^–2 » 1.1 м с⁻²                                                                                                      [1]

c    F = ma = 80 ´ 1.125                                                                                                              [1]
F = 90 Н                                                                                                                               [1]

5    a    i     Время =  = 0.82с                                                                                                      [1]

ii    Пройденный путь  = длина окружности  = 2π ´ 0.80 = 5.03 м » 5.0 м                             [1]

iii   скорость =                                                                                                              [1]
скорость , v = 6.13м с⁻¹ » 6.1 с м⁻¹                                                                                  [1]

iv   a =                                                                                                                            [1]
a =                                                                                                                        [1]
a = 47 м с^–2                                                                                                                     [1]

v    F = ma = 0.090 ´ 47                                                                                                        [1]
F » 4.2 Н                                                                                                                        [1]

6    a    R cos 20° = W = 840 × 9.8                                                                                                      [1]
R =  = 8760 Н                                                                                                         [1]

b    R sin 20° = Центробежная сила =                                                                                 [1]
r =                                                                                                                                [1]
r =                                                                                                                    [1]
r = 287 м » 290 м                                                                                                                  [1]

7    Результативная сила =

Результативная сила =  = 2.4 Н                                                                              [2]

Вес камня W = mg = 0.120 ´ 9.81 = 1.18 Н » 1.2 Н                                                                     [1]

       Вверху:W + T_B = 2.4 so T_B = 2.4 - 1.2 = 1.2 N    [1]

Внизу : T_A - W = 2.4 so T_A = 2.4 + 1.2 = 3.6 N                                                                       [1]

Отношение  =  =  = 3.0                                                                                                   [1]