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Quantity of heat, heat capacity Problem solving solutions and answers.docx
Problem solving solutions and answers
1) Q = mcΔt
c = 2500 J/(kg·°C)
Q = 2 kg·2500 J/(kg·°C)·(40 – 20)°C
Q = 100 kJ
2) Q = mcΔt
c = 4200 J/(kg·°C)
Q = 10 kg·4200 J/(kg·°C)·50°C
Q = 2.1 MJ
3) Q = mcΔt
c = 920 J/(kg·°C)
Q = 0.05 kg·920 J/(kg·°C)·(80 – 20)°C
Q = 2760 J
4) Q = mcΔt
c
= 
c
= 
c = 420 J/(kg·°C)
5) Q = mcΔt
m
= 
tf = 100°C (boiling point of water)
c = 4200 J/(kg·°C)
m
= 
m ≈ 531 kg
6) Q = Q1 + Q2
Q1 = m1·c1·Δt
Q2 = m2·c2·Δt
m1 = ρV
ρ = 1000 kg/m3
tf = 100°C (boiling point of water)
c1 = 4200 J/(kg·°C)
c2 = 920 J/(kg·°C)
Q1 = 1000 kg/m3·2·10-3 m3·4200 J/(kg·°C)·(100-20)°C
Q1 = 672 kJ
Q2 = 0.2 kg·920 J/(kg·°C)·(100-20)°C
Q2 = 14.72 kJ
Q ≈ 687 kJ
7) Q = mcΔt
c = 880 J/(kg·°C)
Q = 1500 kg·880 J/(kg·°C)·(60 – 20)°C
Q = 52.8 MJ
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