Electric field solving problems

𝐹𝐹=𝑘𝑘 𝑞 1 𝑞 2 𝑟 2 𝑞 1 𝑞 1 𝑞𝑞 𝑞 1 1 𝑞 1 𝑞 1 𝑞 2 𝑞 2 𝑞𝑞 𝑞 2 2 𝑞 2 𝑞 2 𝑞 1 𝑞 2 𝑟 2 𝑟 2 𝑟𝑟 𝑟 2 2 𝑟 2 𝑞 1 𝑞 2 𝑟 2

𝐹 𝑞 2 𝐹𝐹 𝐹 𝑞 2 𝑞 2 𝑞 2 𝑞𝑞 𝑞 2 2 𝑞 2 𝑞 2 𝐹 𝑞 2 =𝑘𝑘 𝑞 1 𝑟 2 𝑞 1 𝑞 1 𝑞𝑞 𝑞 1 1 𝑞 1 𝑞 1 𝑞 1 𝑟 2 𝑟 2 𝑟𝑟 𝑟 2 2 𝑟 2 𝑞 1 𝑟 2

𝐸 = 𝐹 𝑞

𝐸 = Н Кл

𝐸= 𝐹 𝑞 =𝑘 𝑞 0 𝑟 2

𝐸= 𝐹 𝑞 =𝑘 𝑞 0 𝑟 2

𝐸= 𝐹 𝑞 =𝑘 𝑞 0 𝑟 2

𝐹

𝐹 𝐹𝐹 𝐹 = 𝐸 𝐸𝐸 𝐸 𝑞𝑞

𝐸= 𝐹 𝑞 =𝑘 𝑞 0 𝑟 2

𝐹

𝐹 𝐹𝐹 𝐹 = 𝐸 𝐸𝐸 𝐸 𝑞𝑞

The effect of the electric field around the charged bodies increases, and the farther away from them is weakened. In order to talk about the magnitude of the electric field acting on a charged body, it is necessary to enter a quantitative description of the field. On the charging body or particle is called the electric force, operating from the side of the field

Let's place the two metal plates parallel to each other. If one of these plates give a charge +q, and the other-q, the distance between the plates is less than their linear dimensions, the stress lines of this field are parallel. The force and direction (uniform) of the field between the plates becomes stable and weak, changing its direction along the edge of the plate.

At each point modulo and direction of the DC electric field is called homogeneous. The voltage lines in a uniform electric field are parallel to each other. The electric field voltage lines are closed, continuous and do not intersect. Depending on what you use these elements, you use them at different points in the field. Uneven field called fields with different densities of stress lines at different points of the field.

𝑞 0 𝑞𝑞 𝑞 0 0 𝑞 0

𝑞 1 𝑞𝑞 𝑞 1 1 𝑞 1

𝑞 3 𝑞𝑞 𝑞 3 3 𝑞 3

𝑞 2 𝑞𝑞 𝑞 2 2 𝑞 2

𝐹 1 𝐹 𝐹𝐹 𝐹 𝐹 1 1 𝐹 1

𝐹 2 𝐹 𝐹𝐹 𝐹 𝐹 2 2 𝐹 2

𝐹 3 𝐹 𝐹𝐹 𝐹 𝐹 3 3 𝐹 3

𝐹 𝑞 0 = 𝐹 1 𝑞 0 + 𝐹 2 𝑞 0 + 𝐹 3 𝑞 0

«Station»

Task descriptors:
• Correctly write the given condition of the problem. Translation to SI units
• To write using formulas
• Correctly write the answer and ways to solve the problem