Lesson objectives
- to study the principle of operation of the heat engine;
- to study of determining the efficiency of a heat engine;
-to be able to solve problems about topic.
Volume
Pressure
Pressure is always on the vertical axis; volume on the horizontal axis.
The PV diagram
Pressure and volume change constantly in a heat engine.
PV diagrams are graphs that are used to illustrate and analyze these changes.
The graph on the right represents a heat engine in which pressure and volume
change as shown.
To illustrate . . .
How much heat was added?
How much work has the engine done?
How efficient is the engine at converting heat into work?
At point a: volume is minimum. From a to b heat is added and pressure rises.
From b to c: gas expands, doing work. In this (unrealistic) example, pressure remains constant as the gas expands.
From c to d: valve opens, reducing the pressure. Heat flows out of the engine to surroundings.
The cycle. . .
At point a: volume is minimum. From a to b heat is added and pressure rises.
From b to c: gas expands, doing work. In this (unrealistic) example, pressure remains constant as the gas expands.
From c to d: valve opens, reducing the pressure. Heat flows out of the engine to surroundings.
From d to a, the piston compresses the gas back to its starting position.
The cycle. . .
The red area is the work done by the system as it expands.
The grey area is the work done on the system to compress it.
The area enclosed by the curve equals the positive net work done by the system in one cycle.
An equal amount of negative work is done on the system.
Work done
Work
This diagram depicts a process that goes from A to B. No heat is added.
Which of the following is true?
The energy of the gas remains constant.
The gas does work on its surroundings and loses energy.
The surroundings do work on the gas and the gas gains energy.
Practice with PV diagrams
This diagram depicts a process that goes from A to B. No heat is added.
Which of the following is true?
The energy of the gas remains constant.
The gas does work on its surroundings and loses energy.
The surroundings do work on the gas and the gas gains energy.
Practice with PV diagrams
Why?
Which part of the process compresses the gas. How do you know?
Does the complete cycle absorb or give off heat? How do you know?
Compression reduces volume. This happens in process C.
For this PV diagram shown:
ΔE = 0 in a complete cycle. Since the system does positive work equal to the enclosed area, Q must have been absorbed.
Practice with PV diagrams
Assume that 100 moles of an ideal gas is taken through the cycle depicted in this PV diagram.
To find the efficiency of the engine, you must calculate work output of the engine, and the heat input.
Efficiency of a heat engine
Pressure
(atm)
1
3
1
4
Volume
(m3)
Next, calculate the internal energy of the gas, U.
U equals the average kinetic energy of each molecule multiplied by the number of molecules, N:
This can be rewritten in terms of moles, n:
Internal energy of a gas
where:
n = # moles of gas R = 8.31 J/mol-K
Check your answers:
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | +300,000 J | ||
b to c | +1,350,000 J | ||
c to d | -1,200,000 J | ||
d to a | -450,000 J |
Heat added or removed
Pressure
(atm)
1
3
1
4
Volume
(m3)
Use the energies from Table 1 to find the change in energy ΔE for each part of the cycle.
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +1,350,000 J | |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -450,000 J |
Determine the work done
Pressure
(atm)
1
3
1
4
Volume
(m3)
Check your answers:
Calculate the work done ON the gas in each part of the cycle. (1 atm ≈ 100,000 Pa)
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +1,350,000 J | |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -450,000 J |
Heat added or removed
Pressure
(atm)
1
3
1
4
Volume
(m3)
Apply conservation of energy to find the heat Q added or removed:
Apply conservation of energy to find the heat Q added or removed:
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +2,250,000 J | +1,350,000 J |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -750,000 J | -450,000 J |
Heat added or removed
Pressure
(atm)
1
3
1
4
Volume
(m3)
Check your answers:
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +2,250,000 J | +1,350,000 J |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -750,000 J | -450,000 J |
TOTALS | -600,000 J | +600,000 J | 0 J |
Efficiency of the cycle
Pressure
(atm)
1
3
1
4
Volume
(m3)
Calculate the efficiency on your answer sheet:
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +2,250,000 J | +1,350,000 J |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -750,000 J | -450,000 J |
TOTALS | -600,000 J | +600,000 J | 0 J |
Efficiency of the cycle
Pressure
(atm)
1
3
1
4
Volume
(m3)
Check your answer:
This thermodynamic cycle has a miserable efficiency of 25%.
Heat not converted to work is rejected to the surroundings in segments c to d and d to a.
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +2,250,000 J | +1,350,000 J |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -750,000 J | -450,000 J |
TOTALS | -600,000 J | +600,000 J | 0 J |
Efficiency of the cycle
No heat engine can convert 100% of heat input to work output.
There are no perfect engines.
This is a consequence of the second law of thermodynamics – the law of entropy.
Part of cycle | Work done | Heat added or removed | Δ Energy |
a to b | 0 J | +300,000 J | |
b to c | -900,000 J | +2,250,000 J | +1,350,000 J |
c to d | 0 J | -1,200,000 J | |
d to a | +300,000 J | -750,000 J | -450,000 J |
TOTALS | -600,000 J | +600,000 J | 0 J |
The work done is always LESS than the heat added.
Efficiency of the cycle
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