Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
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Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Оценка 4.6
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ppt
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10 кл—11 кл
17.05.2018
Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
The presentation includes all the necessary material for review of Chapter 6.1 The Rule for Differentiation for A-level Pure Mathematics Cambridge International Examinations. It will be useful for students as the review materials and also for teachers as the teaching tips and presentations in the class. The presentation was made by Oleksii Khlobystin (Alex) - Mathematics Teacher at Depu Foreign Language School, Chongqing City, China. Personal website: www.visualcv.com/o-khlobystin Personal email: [email protected] POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709 Made by Oleksii Khlobystin (Alex) - Mathematics Teacher at Depu Foreign Language School – Cambridge International Centre, Chongqing City, China. Personal website: www.visualcv.com/o-khlobystin Personal email: [email protected]
Chapter 6.1 The Rule for Differentiation-Alex.ppt

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
The Gradient of a Straight given by Line 1212xxyymwhere and are points on the line ),(11yx),(22yx The gradient of a straight line is The Gradient of a Straight Line

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
the points with coordinates and)1,1()7,3( 1212xxyym3261317m)7,3(x)1,1(x difference in the y-values difference in the x- values 7 ­ 1 = 6 3 ­ 1 = 2 e.g. Find the gradient of the line joining Solution: difference in the x-valuesdifference in the y-values

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
values the in difference the values- the in difference thexym We use this idea to get the gradient at a point on a curve Gradients are important as they measure the rate of change of one variable with another. For the graphs in this section, the gradient measures how y changes with x The gradient of a straight line is given by This branch of Mathematics is called Calculus

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
Curve The Gradient at a point on a Definition: The gradient of a point on a curve equals the gradient of the tangent at that point. e.g. ),(42Tangent 4312mSo, the gradient of the curve at (2, 4) The gradient of the tangent at (2, 4) is is 4 y  2x 12 (2, 4)x 3 at The Gradient at a point on a Curve

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
a curve e.g. y 6mThe gradient changes as we move along 2x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
2x y 4m

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
2x y 2m

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
2x y  0m

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
y  2m 2x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
y  4m 2x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
y  6m 2x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
For the curve we have the following gradients: 2xyPoint on the Gradient)4,2()9,3()1,1()0,0()1,1()4,2()9,3( 6420246At every point, the gradient is twice the x- curve value

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
For the curve we have the following gradients: 2xyGradient6420246)4,()9,()1,()0,0()1,()4,()9,(211233At every point, the gradient is twice the x- Point on the curve value

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
twice the x-value2xyThis rule can be written asxdxdy2The notation comes from the idea of the gradient of a line being the ifference in the -valuesthe ifference in the - valuesd At every point on the gradient is d y x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
twice the x-value2xyThis rule can be written asxdxdy2The notation comes from the idea of the the ifference in the -valuesthe ifference in the - values is read as “ dy  by dx ”dxdyThe function giving the gradient of a curve is At every point on the gradient is called the gradient function gradient of a line being d d y x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
functions 23xdxdy3xy 34xdxdy4xy45xdxdy5xyThe rule for the gradient function of a curve of the form nxy1nnxdxdyis gradients at points on the curve3xyOther curves and their gradient Although this rule won’t be proved, we can illustrate it for by sketching the  “power to the front and  “subtract 1 from the power” multiply” Other curves and their gradient functions

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
y3xy 3xyGradient dxdy)27,3(x of

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
)12,2(x)27,3(x dxdyy 3xy 3xyGradient of

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
dxdyy 3xy 3xyGradient of )27,3(x)12,2(x)3,1(x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
3xyy 3xyGradient of )27,3(x dxdy)12,2(x)3,1(x)0,0(x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
3xyy 3xyGradient dxdy)27,3(x)12,2(x)3,1(x)0,0(x )3,1(x of

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
3xyy 3xyGradient dxdy)27,3(x)12,2(x)3,1(x)0,0(x )3,1(x )12,2(x of

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
3xyy 3xyGradient dxdy)27,3(x)12,2(x)3,1(x)0,0(x )3,1(x )12,2(x )27,3(x of

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
y 23xdxdy3xy dxdy)27,3(x)12,2(x)3,1(x)0,0(x )3,1(x )12,2(x )27,3(x

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
know their gradients xy1y 1yxyThe gradients of the functions and can also be found by the rule but as they represent straight lines we already gradient = gradient = 0 1

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
Functions: 34x23x45xx21dxdy3x4x5x2xxy10Summary of Gradient Summary of Gradient Functions:

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
Point e.g.1 Find the gradient of the curve at The Gradient Function and Gradient at a the point (2, 12). 3xydxdyAt x = 2,  the n: 3xy23x12 gradient 2)2(3dxdymSolutio The Gradient Function and Gradient at a Point

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
3xy8121,23xdxdySolution 43221213,mxAt the point where x  1 4xyAt   x = ­ 1,   m =  ­434xdxdySolution Exercise point : : 1. Find the gradient of the curve at s 2. Find the gradient of the curve at the Exercises

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
 The process of finding the gradient where a is a constant. naxy The rule for differentiating can be extended to curves of the form function is called differentiation.  The gradient function is called the derivative.

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
by 2 3xy 3xytangent at x =  More Gradient Functions e.g. Multiplying by 2 multiplies the gradient gradient =  3 1 tangent at x = 1 More Gradient Functions

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
by 2 3xy3xytangent at x =  32xygradient =  tangent at x =  1 6 e.g. Multiplying by 2 multiplies the gradient gradient =  3 1 tangent at x = 1 tangent at x = 1

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
constantnxThe rule can also be used for sums and 32xy 232xdxdy26xMultiplying by a constant, multiplies the gradient by that differences of terms.  bx c cx d  e.g. 2+ bx ax 3 +2   2 For y  3 ax dy dx For y  n   1 i i  a x i  c dy dx  n   1 i   a i x i i  1

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
e.g. 3752123xxxydxdy 710232xx2321xx257 on the curve 42323xxxySolution function: 1492xxdxdyWhen x = 1, gradient m  1)1(4)1(9212mUsing Gradient e.g. Find the gradient at the point where x = 1 =  Functions : Differentiating to find the gradient Using Gradient Functions

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
 The gradient at a point on a curve is defined as the gradient of the tangent at that point  The function that gives the gradient of a curve at any point is called the gradient function SUMMARY 1nanxdxdynaxyis  The process of finding the gradient function is called differentiating • “power to the front and • “subtract 1 from the multiply” power”  The rule for differentiating terms of the form SUMMARY

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
following curves: 1. 375223xxxy at the point )1,1( n 3,1mx4,1mxWhe 71062xxdxdy26122xxdxdy2xdxdyFind the gradients at the given points on the point )5,1( 2. 423423xxxy at the point )1,2(Whe 3. 12221xxy at the n 0,2mxWhe Exercise s n Exercises

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709

Presentation POWER POINT Chapter 6.1 The Rule for Differentiation, A-level Pure Mathematics CIE 9709
4. )4)(2(xxy at )9,1( rule )822xxy 22xy22xdxdy xdxdy2at )2,2(xxxxy23 0,1mxWhe xxxy235. n42mxWhe ( Multiply out the brackets before using the rule ) (Divide out before using the Exercise s Find the gradients at the given points on the following curves: n Exercises
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17.05.2018